Răspunsuri

2014-09-22T16:54:54+03:00
Teorema impartirii cu rest
a=bxq+r
a+b=2289
a=bx17+111
a=2289-b
2289-b=17b+111
2289-111=17b+b
2178=18b
b=121
a=2289-121=2168
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