Răspunsuri

2014-09-22T09:54:51+03:00
D₁₈=multimea divizorilor lui 18, D₁₈={-18, -9,-6,-3,-2,-1,1,2,3,2,9,18}
x
I 12  x e natural atunci  A={1,2,3,4,6,12}
a)  A n D₁₈={1,2,3,6}
b) A U
D₁₈={{-18, -9,-6,-3,-2,-1,1,2,3,4,6,12,18}
c) A-D₁₈={4,12}
1 5 1
2014-09-22T10:29:09+03:00
D₁₈={-18, -9,-6,-3,-2,-1,1,2,3,2,9,18}
x
 I 12  x e natural =>  A={1,2,3,4,6,12}
a)  A n D₁₈={1,2,3,6}
b) A U 
D₁₈={{-18, -9,-6,-3,-2,-1,1,2,3,4,6,12,18}
c) A-D₁₈={4,12}