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2014-09-20T18:42:21+03:00
CaCO3 + 2 HCl ---> CaCl2 + H2O + CO2
100 g CaCO3.........2*36,5 g HCl......44 g CO2
x g CaCO3...............b h HCl.............132 g CO2
x = 300 g CaCO3
puritatea = x/a * 100 => a = 300/80 * 100 = 375 g CaCO3
b = 219 g HCl
c%=md/ms * 100 => ms = 219/20 * 100 = 1095 g solutie 
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