Răspunsuri

2014-09-20T19:03:52+03:00
( x-5)^{2} =x-3
 x^{2} -10x+25-x+3=0
 x^{2} -11x+28=0
Δ=121-112=9
 x_{1} = \frac{11+3}{2} =7
 x_{2} = \frac{11-3}{2} =4

S={4;7}
1 5 1