Răspunsuri

2014-09-20T10:29:05+03:00
X+1+  \frac{2}{x-1} )*  \frac{x^2-2x+1}{x^3-x^2+x-1} = \frac{(x+1)(x-1)+2}{x-1} * \frac{(x-1)^2}{x^2(x-1)+(x-1)}

E(x)= \frac{x^2+1}{x-1} * \frac{(x-1)^2}{(x^2+1)(x-1)}

E(x)= \frac{x^2+1}{x-1}  \frac{x-1}{x^2+1}

E(x)=1 (dupa simplificare)