Răspunsuri

2014-09-19T03:48:21+03:00
1)
a) (x + 2)² = 16
x + 2 = ±√16
x1 = 4 - 2 = 2
x2 = -4 - 2 = -6

b) |x-3| = 6
x - 3 = ± 6
x1 = 6 + 3 = 9
x2 = -6 + 3 = -3

2)
a) 3x
³ + 6x² + 3x = 3x(x² + 2x + 1) = 3x(x+1)² = 3 * x * (x + 1) * (x + 1)
b) (x + 1)
² - 9 = (x + 1 - 3)(x + 1 +3) = (x - 2)(x + 4)
 




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