Răspunsuri

2014-09-18T17:59:41+03:00
(x+2)!/(x-3)!= (x-3)!(x-2)(x-1)x(x+1)(x+2)/(x-3)!=    se reduc (x-3)! si  o sa ramana 

x(x-2)(x-1)(x+1)(x+2)