Răspunsuri

  • Utilizator Brainly
2014-09-16T02:17:27+03:00
(3x-7)/(2x+3) Z => (2x+3) | (3x-7) => (2x+3) | -2(3x-7) => (2x+3) | (-6x+14). ca (2x+3) | 3(2x+3),  (2x+3) | (6x+9)., (2x+3) | [(-6x+14)+(6x+9)] => (2x+3) | 23., 23  D_23={-1,1,-23,23}.Caz1: 2x+3=-1 => x=-2 Z;Caz2: 2x+3=1 => x=-1 Z;Caz3: 2x+3=-23 => x=-13  Z;Caz4: 2x+3=23 => x=10 Z;, B={-13,-2,-1,10}.