Răspunsuri

2014-09-14T19:26:07+03:00
 ( \sqrt{2} + \sqrt{3} )^{2}= ( \sqrt{2} )^{2}+2* \sqrt{2}  * \sqrt{3} + ( \sqrt{3} )^{2} =2+2* \sqrt{6} +3=5+2* \sqrt{6}
 ( \sqrt{6}-1 )^{2}= ( \sqrt{6} )^{2} -2* \sqrt{6} *1+ 1^{2} =6-2* \sqrt{6}  +1=7-2* \sqrt{6}
Media aritmetica are formula: medaritm= \frac{a+b}{2} , iar la noi  a=( \sqrt{2} + \sqrt{3} )^{2} si  b=( \sqrt{6}-1 )^{2} .
Deci medaritm= \frac{5+2 \sqrt{6}+7-2\sqrt{6}  }{2} = \frac{12}{2} =6
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