Răspunsuri

2014-09-11T08:50:46+03:00
O idee elementara!

21 - 12 \sqrt{3}  ( a - b)^{2}  a^{2} + b^{2} -2ab <=>
21 =  a^{2} + b^{2} si 12 \sqrt{3} = 2ab => ab = 6 \sqrt{3} ;&#10;
=> a = 2 \sqrt{3} si b = 3 => 21 - 12 \sqrt{3}  (2 \sqrt{3}-3 )^{2} =>  \sqrt{21-12 \sqrt{3} } = /2 \sqrt{3} -3/ = 2 \sqrt{3} -3 pt. ca 2 \sqrt{3} > 3;
Bafta!