Răspunsuri

2014-09-11T01:55:59+03:00
(√6-√3-√2+1)/(√10-√5+√2-1)= 

= [√3(√2-1)-(√2-1)]/[√5(√2-1)+(√2-1)]=

=(√2-1)(√3-1)/(√2-1)(√5+1)=

=(√3-1)/(√5+1)