Răspunsuri

2014-09-10T16:31:42+03:00
%O=masa oxigen/masa alcool * 100
=> masa alcool = 16/21,62 * 100 = 74 g
CnH2n+2O => 14n+18=74=>14n=56=>n=4=>C4H10O
CH3-CH-CH2-CH3      2-butanol
       OH