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2014-09-09T16:43:57+03:00
C2H2 + H2O ---> CH2=CH-OH ---> CH3 - CH = O
nr moli practic = 2,5* 80 /100 = 2 moli acetaldehida
nr moli = masa/masa molara => masa aldehida = 2*44 = 88 g = md
ms = md + m apa = 88+412 = 500 g
c%=md/ms*100=88/500 * 100 = 17.6%
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