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2014-09-05T10:47:29+03:00
Probabilitatea=cazuri favorabile/cazuri total posibile

1)nr naturale de 2 cire de la 1 la 100 sunt : 10...99 adica 99-10+1=90 de numere
probabilitatea= 90/100=9/10

2)x²<900
patratele perfecte pana la 100 sunt 1,4,9,16,25,36,49,64,81,100,in total 10 nr
probabilitatea= 10/100=1/10


3)M6{6,12,24,30,36,42,48,54,60,66,72,78,84,90,96 in total 15 nr 
probabilitatea= 15/100=3/20
4 4 4