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2014-09-04T20:37:45+03:00
x²+2√3x-√3=0
Folosind relatiile lui Viete:
S = 
x_{1}+x_{2}  = -b/a = -2√3
P =  x_{1} x_{2}  = c/a = -√3
 \frac{1}{ x_{1} }+  \frac{1}{ x_{2} } =   \frac{ x_{1} +  x_{2} }{ x_{1} x_{2}  } =  \frac{S}{P} =  \frac{-2 \sqrt{3} }{ -\sqrt{3} } = 2