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2014-09-03T19:41:58+03:00
Ma1=(a+b)/2=28

a+b=28*2
a+b=56

ma2=(x+y+z)/3=58

x+y+z=58*3
x+y+z=174

ma3=(a+b+x+y+z)/5= (174+56)/5=  230/5=46
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  • Utilizator Brainly
2014-09-03T19:45:50+03:00
(a+b)/2=28/*2 .... a+b=56
(c+d+e)/3=58/*3............ c+d+e=174
Ma=(a+b+c+d+e)/5=56+174=230/5=46
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