Răspunsuri

2014-09-01T18:51:12+03:00
(intersectia cu Ox/f(x)=0)=>x²+5x-6=0=> Δ=5²+4*6=49 , x1=(-5+7)/2;x1=1  x2=(-5-7)/2;x2=-6;
f(0)=-6(intersectia cu Oy)
Vf(xv,yv) xv=-b/2a=-5/2
             yv=-Δ/4a=-49/4=-12,25       Vf(-5/2,-49/4)
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