Răspunsuri

2014-09-01T16:12:07+03:00
A=2k
b=3k
c=5k

ab+ac+bc=279
2k*3k+2k*5k+3k*5k=279
6k^2+10k^2+15K^2=279
31k^2=279
K^2=9
k= radical din 9
k=3

a=2*3=6
b=3*3=9
c=5*3=15