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2014-09-01T12:06:15+03:00
ΔABC, mas<A=90
BC=12
Notam AB=AC=x

BC²=AC²+AB²  

12²=x²+x²

144=2x²

x²=72  => x= 6√2

AB=AC=6√2

A ΔABC= AB*AC/2=  6√2* 6√2/2=  18*2=36
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