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2014-08-31T21:27:49+03:00
ΔABC, mas<A=90

AB/AC= 2/3

AB/2=AC/3=k
AB=2k
AC=3k

BC²=AB²+AC²

(12√13)²=(2k)²+ (3k)²

1872=4k² +9k²

1872=13k²

k²=144 =>k=12

AB=2*12=24
AC=3*12=36

b)A ΔABC=AB*AC/2=  24*36/2= 12*36= 432

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