Răspunsuri

2014-08-31T21:40:51+03:00
1) 3^ (x-5) = (3⁹)⁴ : (3²)¹⁰

3^ (x-5)= 3³⁶ : 3²⁰

3 ^(x-5)= 3¹⁶

x-5=16  => x= 16+5= 21

2) a/b= 6/8

a/6=b/8=k

a=6k
b=8k

a+b=70
6k+8k=70
14k=70
k=5

a=6*5=30
b=8*5=40

3)a/x=b/y=c/z =6

a/x=6=> a=6k  ∧  x=k

b/y=6=> b=6k ∧ y=k

c/z=6 => c=6k    ∧ z=k

(a+b+c)/(x+y+z)=  (6k+6k+6k)/(k+k+k)=  18k/3k= 6
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