Răspunsuri

2014-08-28T21:55:24+03:00
2√6<6√2⇒dupa aplicarea modulului a=6√2-2√6=6√2-2√2√3=2√2(3-√3)
b=√72+√24=√24*√3+√24=√24(1+√3)
mg=√(a*b)=√[2√2(3-√3)*√24(1+√3)]=√[2*√48*2*√3]=√(4√144)=√(4*12)=2√12=4√3
1 5 1