Răspunsuri

Cel mai inteligent răspuns!
2014-08-28T13:10:36+03:00
O ecuatie de gradul doi are radacina dubla daca delta =0.
\triangle=b^2-4ac=(m+1)^2-4m=m^2+2m+1-4m=m^2-2m+1\\
\triangle=m^2-2m+1=(m-1)^2\\
\triangle=0\\
(m-1)^2=0=>m-1=0=>m=1
1 5 1