Răspunsuri

2014-08-27T16:21:36+03:00
3*{3+3*[3+3*( 3x-2)]}=9
3*{3+3*[3+3*3x-3*2)]}=9
3*{3+3*[3+9x-6)]}=9
3*[3+3*(9x-3)]=9
3*(3+3*9x-3 *3)=9
3*(3+27* x -9)=9
3*(27*x-6)=9
27*x-6 =9:3
27*x-6 =3
27*x=3+6
27*x=9
x= \frac{9}{27} =   \frac{1}{3}