Răspunsuri

2014-08-27T11:53:08+03:00
%H=100 - 85,714 = 14,282%
85,714/12 = 7,14283
14,282/1 = 14,282
=> FB = (CH2)n
(CH2)n + 3n/2 O2 ---> n CO2 + n H2O
14 n grame hidrocarbura ..........3n/2 * 22,4 l O2
2 * 14 n grame hidrocarbura.........268,8 l O2
=>14n*268,8=2*14n*3n/2*22,4=>268,8=67,2n => n = 4
=> FM = (CH2)4 = C4H8

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