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Cel mai inteligent răspuns!
2014-08-27T09:52:07+03:00
-1  \leq \frac{x+1}{3} < 2 \ \ aducem \ la \ acelasi \ numitor \\\\ -3  \leq  x+1 < 6 \ \ |(-1) \\ \\ -4 \leq x < 5 \\  \\ => \boxed{x = [-4;5) }
inmultesc cu -1?
adaugi -1
-3 -1=-4 ; x+1 -1= x ; 6-1=5
ok
2014-08-27T09:55:42+03:00
-1≤ \frac{x+1}{3}<2|(*3)
-3≤x+1<6 |(-1)
-4≤x<5
x∈ [-4,5)
1 5 1