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Cel mai inteligent răspuns!
2014-08-26T20:46:07+03:00
Plecam de la formula:   pH= - log[H3O+]
a) 11,013= -log[H3O+] => [H3O+] =  10^{-11,013}
b) 4,902= - log[H3O+] => [H3O+]=  10^{-4,902}
c) 7,002= - log[H3O+] => [H3O+]=  10^{-7,002}
d)  6,127= - log [H3O+] => [H3O+]= 10^{-6,127} [/tex]
e) 13,19= -log[H3O+] => [H3O+]=  10^{-13,19}
f) 12,77= -log[H3O+] => [H3O+]=  10^{-12,77}  

sunt niste numere cam ciudate,dar asta e algoritmul corect
  
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