Răspunsuri

2014-08-25T18:21:05+03:00
Notam rombul ABCD, ΔBOA (O-intersectia diagonalelor)- dreptunghic
OA=AC÷2=25÷2
OB=BD÷2=5
BA²=25÷2²+5²=3125
BA=25√5
Prombului= 25√5×4=100√5