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2014-08-25T23:27:11+03:00
ΔABC, mas<A=90
mas<B=60                 =>mas<C=30

AB=BC/2 <=>3√3 =BC/2   =>BC=6√3

AC²=BC²-AB²=  (6√3)² - (3√3)²= 108-27= 81   =>AC=9

cateta opusa <60=AC=9