Răspunsuri

2014-08-25T09:39:47+03:00
Stabilim intai numerele rationale din multimea A.
-2,5= \frac{-25}{10} \in  Q\\
 \sqrt{\frac{4}{9}}= \frac{ \sqrt{4} }{ \sqrt{9} } = \frac{2}{3} \in Q\\
 \sqrt{2}\notin Q\\
 \sqrt{6,25} = \sqrt{\frac{625}{100}}=   \frac{25}{10}\in Q\\
 \sqrt{ \frac{25}{3} } = \frac{5}{ \sqrt{3} } = \frac{5}{3}  \sqrt{3}  \notin Q\\
A\cap Q=\{-2,5;\sqrt{\frac{4}{9}}; \sqrt{6,25}\}
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