Răspunsuri

2014-08-24T11:39:01+03:00
 x⁴+y²+4=x²·y+2(x²+y)
x
⁴+y²+4=x²·y+2x²+2y
x⁴+y²+4=3x²+2y²
x⁴-3x²+4=-y²+2y² 
x⁴-3x²+4=y²⇒nu exista x,y