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2014-08-21T18:06:33+03:00
Punctele de intersectie se gasesc folosind conditia :f(x)=g(x)
-x+1=3x^2-3x+1\\
3x^2-2x=0\\
x(3x-2)=0\\
x_1=0;x_2=\frac{2}{3}\\
y_1=f(0)=1\\
y_2=f( \frac{2}{3})=- \frac{2}{3}+1=\frac{1}{3} \\
G_f \cap G_g=\{A(0;1),B( \frac{2}{3}; \frac{1}{3}) \}
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