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2014-08-17T16:25:38+03:00
X/6  x-prim, x ≤ 11

probabilitatea=nr cazurilor favorabile/nr cazurilor posibile

nr cazurilor favorabile

1/6= 0,1(6)
2/6=1/3= 0,(3)
3/6= 1/2= 0,5  -fractie zecimala finita
4/6= 2/3= 0,(6)
5/6=0,8(3)
6/6=1  -fractie zecimala finita
7/6=1,1(6)
8/6=4/3=1,(3)
9/6=3/2= 1,5  -fractie zecimala finita
10/6= 5/3= 1,(6)
11/6=1,8(3)

p= 3/11
1 5 1