Răspunsuri

2014-08-16T12:45:19+03:00
ΔABC, mas<A=90

AB/AC=3/4

AB/3=AC/4=k

AB=3k
AC=4k

BC²=AB²+AC²

(10√3)²= (3k)² +(4k)²

300= 9k²+16k²

25k²=300

k²=12  =>k= 2√3

AB=3*2√3=6√3
AC=4*2√3=8√3

A ΔABC=AB*AC/2=  6√3 *8√3/2=  3√3*8√3= 24*3= 72