Răspunsuri

2014-08-14T19:55:29+03:00


-  (-81)la putera a 17-a    = -3 la puterea 4·17= -(3)^68   

-    12^99=3^99·2^198           3^99·2^198- 3^66= 3^66(3^33·2^198-1)

-3^68÷3^66(3^33·2^198-1)=-3^2/(3^33·2^198-1)=-9/(3^33·2^198-1)

-   8^33=2^99

-9/(3^33·2^198-1) +2^99=([-9+ 3^33·2^297-2^99)]/(3^33·2^198-1)

 

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