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2014-08-14T16:29:11+03:00
1)-5 < | 2x+1| < 5

-5 <2x+1 < 5 |-1

-6 < 2x < 4 |:2

-3 < x < 2

A= { -2;-1;1}

2)\frac{15}{x+3} \ apartine\  N \\ x \ apartine \ Z  => (x+3)|15  <=> x+3= [1,3,5,15]  \\ 1) x+3=1 =>x=1-3=-2 \\ 2)x+3=3 =>x=3-3=0 \\ 3)x+3=5 =>x=5-3=2 \\4)x+3=15 =>x=15-3=12 \\ B=[-2;0;2;12]
1 5 1