Sa se afle valorile lui x din egalitatile :

3 5 7 21 11x

a) 3 * 3 * 3 * 3 *...* 3 = 3

3 5 17 9x

b) 2 * 2 * 2 * ... * 2 = 2

2x 4x 6x 20x 22

c) 2 * 2 * 2 * ... * 2 = 1024

x 3x 5x 21x 11 22

d) 3 * 3 * 3 * ... *3 = (3 )

cineva sa ma ajute :(

1

Răspunsuri

2014-08-16T22:58:53+03:00
A) 1+3+5+7+9+11+13+15+17+19+21 = 11x
121 = 11x ⇒ x = 121/11 = 11

b) 1+3+5+7+9+11+13+15+17 = 9x
81 = 9x ⇒ x = 81/9 = 9

c) 1024 = 2 la puterea 10
2x+4x+6x+8x+10x+12x+14x+16x+18x+20x = 220
110x = 220 ⇒ x = 220/110 = 2

d) x+3x+5x+7x+9x+11x+13x+15x+17x+19x+21x = 1122
121x = 1122 ⇒ x = 242/121 = 2