Răspunsuri

2014-02-10T18:14:55+02:00
A+b+c=126
a=2b  deci b= \frac{a}{2}
c= \frac{a}{2}
se inlocuiesc b si c in functie de a
a+ \frac{a}{2} + \frac{a}{2} =126
 se aduc la acelasi numitor amplificandu-se cu 2 primul numar
 \frac{2a +2a}{2} =126
 \frac{4a}{2}
a= \frac{126*2}{4}
a= 63
b=63/2
c=b
2 4 2