Răspunsuri

2014-08-08T15:41:41+03:00
1-x+2-x/2+3-x/3=4-x/4-5-x/5-(6-x)
6-x-x/2-x/3=-1-x/4-x/5-6+x transferam necunoscutele intr-o parte
6+7=2x-x/2-x/3-x/4-x/5  se aduce la acelasi numitor in partea dreapta
13=(120+30+20-15-12)*x/60
13=143/60*x
11*x=60...
2 3 2