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2014-08-07T18:01:11+03:00
ΔABC

AB=2          =>AB²=4
AC=4√3     =>AC²=(4√3)²= 48
BC=2√13   =>BC²=(2√13)²= 52

4+48=52
AB²+AC²=BC²      =>ΔABC -dreptunghic, mas<A=90

fie [AD] _|_ [BC]
AD-h

AD=AB* AC/BC=  2  * 4√3/2√13=  4√3/√13=  4√39/13

ΔADB, mas<D=90

BD²= AB²-AD²=  2² - (4√39/13)²=  4 - 624/169=  (676-624)/169= 52/169

=>BD= 2√13/13

DC=BC-BD=  2√13 -2√13/13=  (26√13 -2√13)/13= 24√13/13
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