1.) 12√6 : (4√3) =
30√14 : ( -5√2) =
8√18: √6
2.) Aratati ca numerele a,b si c sunt intregi :
a= 4√10 - 2√8 - (6+4√10)
b= 2(4+√21) - 6√7+2√7 * (3-√3)
c= 4√3(√8-√3) - 2√2* (3√3-√2)

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Răspunsuri

2014-08-04T12:47:42+03:00
1)12√6 :4√3= 3

30√14 : (-5√2)= -6√7

8√18 :√6= 8√3

2)a= 4√10 -2√8 -6 -4√10= -2√8 -6=  -2*2√2 -6= -2(2√2+3)

b=8+2√21-6√7+6√7 -2√21=

b=8+6√7-6√7

b=8

c=4√24 -4*3 -6√6 -2*2=

=4*2√6 -12 -6√6 -4=

=8√6-6√6 -16=

=2√6 -16=  2(√6-8)