Răspunsuri

2014-07-31T00:12:24+03:00
ABCD-romb
AB=BC=CD=AD=10
AC;BD-diag
BD=12

fie [AM _|_ DB
AM-h
M-mij lui DB  <=> DM=MB=BD/2= 12/2= 6

ΔAMB, mas<M=90  =>AM²=AB²-MB²=  10² -6²  =100-36=64  =>AM=8

AC intersectat DB ={M}  <=> M-mij lui AC

AM=MC=AC/2  =>AC=2AM=2*8=16

A ABCD= d1 *d2 /2=  AC*BD/2=  16*12/2=  8*12=  96