Răspunsuri

2014-02-10T13:04:10+02:00
A+b+c = 999
a=2b
c= (a+b)/2

Inlocuim in prima ecuatie:

2b+b+ 3b/2 = 999 => 3b+3b/2 = 999 Aducem la celasi numitor amplificand prima fractie cu 2 => 6b/2 + 3b/2 = 999 => 9b/2 = 999 => 9b = 2*999 => b = 2*999/9 => b= 2*111 = 222 => a=2b = 444 => c=(a+b)/2= 666/2 = 333

a= 444 b=222 c=333