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2014-07-28T18:28:30+03:00
Se formeaza ΔAOB-isoscel

AO=OB=R=20
AB=32

fie OD_|_ AB =>d(O;AB)=OD

A ΔAOB= b*h/2= AB*OD/2= 32*OD/2= 16*OD

A ΔAOB= √p(p-a)(p-b)(p-c)

p=(a+b+c)/2=  (20+20+32)/2= 72/2=36

A ΔAOB= √36*(36-20)(36-20)(36-32)=

=√6² *16 *16 * 4=

=√6² *4² *4² *2²=

= 6*4*4*2=

=192

A ΔAOD=192

A ΔAOD=16*OD

16*OD=192   =>OD=12  =>d(O;AB)=OD=12