Răspunsuri

2014-07-27T20:36:52+03:00
1) AB= √ (3+2)² + (1+4)²=  √5² +5² = √ 25+25= √50= 5√2

2)[(4x+1)-(2x+3)][(4x+1)+(2x+3)]=  (4x+1-2x-3)(4x+1+2x+3)=

=(2x-2)(6x+4)= 2(x-1)(3x+2)

3)4x² -4x +1 +9y² +12y +4=0

(2x-1)² +(3y+2)²=0

|2x-1|=0  ∧  |3y+2|=0
2x-1=0         3y+2=0
2x=1              3y= -2
x= 1/2              y= -2/3
l-am descompus pentru a forma binomuri 4x^2 -4x ( +1) + 9y^2 +12y (+4)
mersi scz
;) n-ai de ce
bn
:)