Răspunsuri

2014-07-27T20:58:27+03:00
AB=√(2+1)² +(1-2)²=  √3² +(-1)²=  √9 +1=  √10

C∈ [AB]

CA/CB=2

(CA+CB)/CB=2

AB/CB=2

√10/CB=2

CB=√10/2

CB+CA=AB

CA=AB-CB=  √10- √10/2   aducem la acelasi numitor

CA= (2√10-√10)/2=   √10/2  =>C-mij lui AB

x=(2-1)/2=  1/2

y=(1+2)/2 =3/2   =>C(1/2; 3/2)