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2014-07-27T16:43:26+03:00
 \frac{x-1}{2} + \frac{2x+1}{3} = \frac{1-2x+1}{6}
 \frac{3(x-1)+2(2x+1)}{6} = \frac{1-2x+1}{6}
 \frac{3x-3+4x+2}{6} = \frac{1-2x+1}{6}
3x-3+4x+2=1-2x+1
3x+4x+2x=1+1+3-2
9x=3
x= \frac{3}{9}
x= \frac{1}{3}     | => x ∈ Q 
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