Răspunsuri

2014-07-27T15:08:54+03:00
A) din th inaltimii avem
AD²=BD.DC
36=9.BD
BD=36:9=4 cm
b)Din th catetei
AB²=BD.BC
36=BD.10
BD=36/10=18/5
cu th Pitagora in ΔABD avem
AB²=BD²+AD²
AD²=36-18/5=(180-18)/5=162/5
AD=9√10/5  cm