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2014-07-25T19:34:37+03:00
Ca(OH)2 + 2 HCl ---> CaCl2 + 2 H2O
cM=nr moli/volum => nr moli = 0,5 * 1000 = 500 moli HCl
74 g Ca(OH)2..........2 moli HCl
x g Ca(OH)2.........500 moli HCl     x = 18500 g = 18,5 kg lapte de var