Răspunsuri

2014-07-23T15:59:59+03:00
A) 64=8²=4³

b)(225-1²)(225-2²)...(225-16²)
225=15² si in acest sir exista  si (225-15²) =0
inmultin toti ceilalti termeni cu 0 avem
(225-1²)(225-2²)...*0*(225-16²)  =0

c)3+6+9+....2001 =(2001+3)[(2001-3):3+1]:2=2004*
667:2=1002*667=668334